The product in the given reaction is:

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(B) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces aldehydes,ketones,carboxylic acids,and esters to their corresponding

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$C_6H_5-CH=CH-CH_2OH$

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(B) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces aldehydes,ketones,carboxylic acids,and esters to their corresponding alcohols. However,it does not reduce isolated carbon-carbon double bonds $(C=C)$. In the given reaction,the reactant is cinnamaldehyde $(C_6H_5-CH=CH-CHO)$. $LiAlH_4$ selectively reduces the aldehyde group $(-CHO)$ to a primary alcohol group $(-CH_2OH)$ while leaving the conjugated double bond $(C=C)$ intact. Therefore,the product formed is cinnamyl alcohol,which is $C_6H_5-CH=CH-CH_2OH$.

Test	Inference
$(a)$ $2, 4-DNP$ test	Coloured precipitate
$(b)$ Iodoform test	Yellow precipitate
$(c)$ Azo-dye test	No dye formation

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Test Inference

$(a)$ $2, 4-DNP$ test Coloured precipitate

$(b)$ Iodoform test Yellow precipitate

$(c)$ Azo-dye test No dye formation

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