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(A) The reaction involves $\gamma$-butyrolactone reacting with a di-Grignard reagent,$BrMg-(CH_2)_4-MgBr$. $1$. The nucleophilic carbon of the Grignar

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Cyclopentanol derivative with a $-(CH_2)_3-OH$ group

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(A) The reaction involves $\gamma$-butyrolactone reacting with a di-Grignard reagent,$BrMg-(CH_2)_4-MgBr$. $1$. The nucleophilic carbon of the Grignard reagent attacks the carbonyl carbon of the $\gamma$-butyrolactone,leading to the ring opening of the lactone. $2$. The intermediate formed is a di-alkoxide species. $3$. Upon acid hydrolysis $(H_3O^{+})$,the alkoxide groups are protonated to form hydroxyl groups. $4$. The final product is a cyclic structure with a side chain,specifically $1-$($4$-hydroxybutyl)cyclopentan$-1-$ol (or a similar diol derivative depending on the exact cyclization). Based on the provided reaction scheme,the product is a diol where the ring has opened and the Grignard chain has attached.

Identify the product of the following reaction: $\gamma$-butyrolactone + $BrMg-(CH_2)_4-MgBr$ $\xrightarrow[(ii) H_3O^{+}]{(i) THF}$

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Find out the major product from the following reaction.

$CH_3 CH_2 OH \underset{\text{step-}1}{\stackrel{Cl_2}{\longrightarrow}} CH_3 CHO$ $\underset{\text{step-}2}{\stackrel{3 Cl_2}{\longrightarrow}} Cl_3 CCHO$
In the above reactions,the role of $Cl_2$ in step-$1$ and step-$2$ respectively is:

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