What is the product of the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an alkene with $OsO_4$ followed by $NaHSO_3$ is a syn-dihydroxylation reaction.This process adds two hydroxyl $(-OH)$ groups to th

Vedclass · Accepted Answer

$C$

Vedclass · Answer

(C) The reaction of an alkene with $OsO_4$ followed by $NaHSO_3$ is a syn-dihydroxylation reaction.This process adds two hydroxyl $(-OH)$ groups to the same side of the double bond,resulting in the formation of a cis-diol.For $1,2-	ext{dimethylcyclopentene}$,the two $-OH$ groups will be added to the same face of the cyclopentane ring,while the two methyl groups will be pushed to the opposite side.Looking at the options,option $C$ represents the correct stereochemistry where both $-OH$ groups are on the same side (cis) and both $-CH_3$ groups are on the same side (cis).

What is the product of the following reaction?
$1,2-\text{dimethylcyclopentene} \xrightarrow[2. NaHSO_3]{1. OsO_4} \text{Product}$

Similar Questions

In the reaction sequence $Me_3CCH=CH_2 \xrightarrow{Q} Me_3CCH_2CH_2OH$ and $Me_3CCH=CH_2 \xrightarrow{R} Me_3C-CH(OH)-CH_3$, $Q$ and $R$ are respectively:

What is the major product obtained when $1$-butanol is heated with concentrated $H_2SO_4$?

Consider the following reaction sequence:
$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$
The major end product formed is:

Identify the major products $X$ and $Y$ in the following reactions:
$(i)$ $C_6H_5-CH=CH_2 + HBr \rightarrow X$
(ii) $C_6H_5-CH_2-CH=CH_2 + HBr \xrightarrow{\text{Peroxide}} Y$

$2$-methyl-$2$-butene will be represented as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the product of the following reaction?$1,2-\text{dimethylcyclopentene} \xrightarrow[2. NaHSO_3]{1. OsO_4} \text{Product}$