The product of this reaction is:

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(A) The reaction of $2$-aminodiphenylmethane with $NaNO_2$ and $H_2SO_4$ (diazotization) forms a diazonium salt intermediate.This diazonium salt then

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Fluorene

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(A) The reaction of $2$-aminodiphenylmethane with $NaNO_2$ and $H_2SO_4$ (diazotization) forms a diazonium salt intermediate.This diazonium salt then undergoes an intramolecular electrophilic aromatic substitution reaction.The diazonium group acts as an electrophile,attacking the other benzene ring to form a new $C-C$ bond,resulting in the formation of fluorene.

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