Prolonged exposure of chloroform in humans may cause damage to the liver. It is due to the formation of the following compound.

$2-$bromopentane is heated with potassium ethoxide in ethanol. The major product is

Observe the following reactions:
$1$. $C_6H_5-CH=CH_2 + HBr \rightarrow X$
$2$. $C_6H_5-C(CH_3)=CH_2 + HBr \rightarrow Y$
$3$. $C_6H_5-CH=CH_2 + HBr \xrightarrow{(C_6H_5COO)_2} Z$
The correct order of reactivity of $X, Y, Z$ towards $S_N1$ reaction is:

From each of the following pairs,select the compound that will react faster with sodium iodide in acetone:
Pair-$A$: $(1) \, 2-$Chloropropane,$(2) \, 2-$Bromopropane
Pair-$B$: $(3) \, 1-$Bromobutane,$(4) \, 2-$Bromobutane

What is the product formed when $CH_3-CH=CHBr$ reacts with $HBr$ in the presence of peroxide?

Which of the following is the correct decreasing order of the boiling point of the given compounds?