Rachana had an average score of 45 from 6 tes | vedclass

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(C) The initial average score of $6$ tests is $45$. Therefore,the total sum of the scores for $6$ tests is $45 	imes 6 = 270$. After dropping the low

Vedclass · Accepted Answer

$\frac{(45 	imes 6 - 30)}{5}$

Vedclass · Answer

(C) The initial average score of $6$ tests is $45$. Therefore,the total sum of the scores for $6$ tests is $45 	imes 6 = 270$. After dropping the lowest score of $30$,the new sum of the scores becomes $270 - 30 = 240$. The number of remaining tests is $6 - 1 = 5$. The new average score is calculated by dividing the new sum by the number of remaining tests: $\frac{240}{5} = 48$. Representing this in the given format,the expression is $\frac{(45 	imes 6 - 30)}{5}$.

Class	$0-20, 20-40, 40-60, 60-80, 80-100, 100-120$
Frequency	$10, f, 7, 6, 5, 4$

Rachana had an average score of $45$ from $6$ tests. Her teacher dropped her lowest score,which is $30$,and calculated the average of the remaining scores to decide her grade. Which of the following gives her new average score?

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