In the formula $\bar{x} = a + \frac{\sum f_{i} d_{i}}{\sum f_{i}}$ for finding the mean of grouped data,$d_{i}$ are deviations from $a$ of:
- Alower limits of the classes
- Bupper limits of the classes
- Cmid points of the classes
- Dfrequencies of the class marks
Explore More
Similar Questions
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is $Rs. 18$. Find the missing frequency $f$.
Daily pocket allowance (in $Rs.$) $11-13$ $13-15$ $15-17$ $17-19$ $19-21$ $21-23$ $23-25$ Number of children $7$ $6$ $9$ $13$ $f$ $5$ $4$
| Daily pocket allowance (in $Rs.$) | $11-13$ | $13-15$ | $15-17$ | $17-19$ | $19-21$ | $21-23$ | $23-25$ |
| Number of children | $7$ | $6$ | $9$ | $13$ | $f$ | $5$ | $4$ |
Difficult
View SolutionIn the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$\Sigma f_{i}$ represents ........
Easy
View SolutionConsider the following distribution:
Marks obtained Number of students More than or equal to $0$ $63$ More than or equal to $10$ $58$ More than or equal to $20$ $55$ More than or equal to $30$ $51$ More than or equal to $40$ $48$ More than or equal to $50$ $42$
The frequency of the class $30-40$ is:
| Marks obtained | Number of students |
| More than or equal to $0$ | $63$ |
| More than or equal to $10$ | $58$ |
| More than or equal to $20$ | $55$ |
| More than or equal to $30$ | $51$ |
| More than or equal to $40$ | $48$ |
| More than or equal to $50$ | $42$ |
The frequency of the class $30-40$ is:
Easy
View SolutionThe distribution below shows the number of wickets taken by bowlers in one-day cricket matches. Find the mean number of wickets by choosing a suitable method. What does the mean signify?
Number of wickets $20$-$60$ $60$-$100$ $100$-$150$ $150$-$250$ $250$-$350$ $350$-$450$ Number of bowlers $7$ $5$ $16$ $12$ $2$ $3$
| Number of wickets | $20$-$60$ | $60$-$100$ | $100$-$150$ | $150$-$250$ | $250$-$350$ | $350$-$450$ |
| Number of bowlers | $7$ | $5$ | $16$ | $12$ | $2$ | $3$ |
Medium
View SolutionThe mean of $10$ observations is $15.7$. If a new observation $19$ is included,the new mean is ..........
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo