The radius of the Earth is approximately 6000 | vedclass

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(B) The acceleration due to gravity at a height $h$ above the Earth's surface is given by the formula: $g' = g \left( \frac{R}{R + h} \right)^2$.Given

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One-fourth

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(B) The acceleration due to gravity at a height $h$ above the Earth's surface is given by the formula: $g' = g \left( \frac{R}{R + h} \right)^2$.Given that the radius of the Earth $R = 6000 \, km$ and the height $h = 6000 \, km$,we have $h = R$.Substituting this into the formula: $g' = g \left( \frac{R}{R + R} \right)^2 = g \left( \frac{R}{2R} \right)^2 = g \left( \frac{1}{2} \right)^2 = \frac{g}{4}$.Since weight $W = mg$,the weight at height $h$ becomes $W' = mg' = \frac{mg}{4} = \frac{W}{4}$.Therefore,the weight of the body becomes one-fourth of its weight on the Earth's surface.

The radius of the Earth is approximately $6000 \, km$. The weight of a body at a height of $6000 \, km$ from the Earth's surface becomes:

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