Range of the function f(x) = 9 - 7 sin x is | vedclass

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(B) We know that for any real number $x$,the range of $\sin x$ is $[-1, 1]$.Thus,$-1 \le \sin x \le 1$.Multiplying by $-7$,we get $-7 \le -7 \sin x \l

Vedclass · Accepted Answer

$[2, 16]$

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(B) We know that for any real number $x$,the range of $\sin x$ is $[-1, 1]$.Thus,$-1 \le \sin x \le 1$.Multiplying by $-7$,we get $-7 \le -7 \sin x \le 7$ (note the inequality signs flip).Adding $9$ to all parts,we get $9 - 7 \le 9 - 7 \sin x \le 9 + 7$.This simplifies to $2 \le f(x) \le 16$.Therefore,the range of the function is $[2, 16]$.

Range of the function $f(x) = 9 - 7 \sin x$ is

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