Rate of flow of heat through a cylindrical rod is $H_1$. The temperatures at the ends of the rod are $T_1$ and $T_2$. If all the dimensions of the rod become double and the temperature difference remains the same,the rate of flow of heat becomes $H_2$. Then:

  • A
    $H_2 = 4H_1$
  • B
    $H_2 = 2H_1$
  • C
    $H_2 = \frac{H_1}{2}$
  • D
    $H_2 = \frac{H_1}{4}$

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