Rationalise the denominator of the following:
$\frac{2}{3 \sqrt{3}}$

  • A
    $\frac{2 \sqrt{5}}{7}$
  • B
    $\frac{6 \sqrt{7}}{9}$
  • C
    $\frac{5 \sqrt{3}}{9}$
  • D
    $\frac{2 \sqrt{3}}{9}$

Explore More

Similar Questions

Rationalise the denominator of $\frac{1}{\sqrt{2}}$.

Rationalise the denominator of the following expression:
$\frac{4}{\sqrt{10}+\sqrt{6}}$

Find the value of $a$ :
$\frac{5+2 \sqrt{3}}{7+4 \sqrt{3}}=a-6 \sqrt{3}$

Difficult
View Solution

The number obtained on rationalizing the denominator of $\frac{1}{7-\sqrt{2}}$ is

Simplify the following:
$3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo