Simplify the following:3 sqrt{3}+2 sqrt{27}+f | vedclass

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(B) Given expression: $3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$First,simplify $\sqrt{27}$:$\sqrt{27} = \sqrt{9 	imes 3} = 3 \sqrt{3}$Substitute thi

Vedclass · Accepted Answer

$\frac{34}{3} \sqrt{3}$

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(B) Given expression: $3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$First,simplify $\sqrt{27}$:$\sqrt{27} = \sqrt{9 	imes 3} = 3 \sqrt{3}$Substitute this into the expression:$=3 \sqrt{3}+2(3 \sqrt{3})+\frac{7}{\sqrt{3}}$$=3 \sqrt{3}+6 \sqrt{3}+\frac{7}{\sqrt{3}}$Rationalize the denominator of the third term:$\frac{7}{\sqrt{3}} = \frac{7 	imes \sqrt{3}}{\sqrt{3} 	imes \sqrt{3}} = \frac{7 \sqrt{3}}{3}$Now add the terms:$=3 \sqrt{3}+6 \sqrt{3}+\frac{7 \sqrt{3}}{3}$$=9 \sqrt{3}+\frac{7 \sqrt{3}}{3}$$= \sqrt{3} \left(9+\frac{7}{3}ight)$$= \sqrt{3} \left(\frac{27+7}{3}ight)$$= \frac{34}{3} \sqrt{3}$

Simplify the following:
$3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$

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Simplify the following:$3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$