Find five rational numbers between -frac{2}{3 | vedclass

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Question

(B) To find five rational numbers between $-\frac{2}{3}$ and $\frac{1}{5}$,first make the denominators equal by finding the least common multiple $(LC

Vedclass · Accepted Answer

-$1$/$3$,-$2$/$9$,-$1$/$9$,$0$,$1$/$9$

Vedclass · Answer

(B) To find five rational numbers between $-\frac{2}{3}$ and $\frac{1}{5}$,first make the denominators equal by finding the least common multiple $(LCM)$ of $3$ and $5$,which is $15$.$-\frac{2}{3} = -\frac{2 	imes 5}{3 	imes 5} = -\frac{10}{15}$$\frac{1}{5} = \frac{1 	imes 3}{5 	imes 3} = \frac{3}{15}$Now,we need to find five rational numbers between $-\frac{10}{15}$ and $\frac{3}{15}$.The integers between $-10$ and $3$ are $-9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2$.We can choose any five from these,for example: $-\frac{9}{15}, -\frac{8}{15}, -\frac{7}{15}, -\frac{6}{15}, -\frac{5}{15}$.Simplifying these,we get: $-\frac{3}{5}, -\frac{8}{15}, -\frac{7}{15}, -\frac{2}{5}, -\frac{1}{3}$.

Find five rational numbers between $-\frac{2}{3}$ and $\frac{1}{5}$.

Similar Questions

Find the values of $a$ and $b$ in each of the following:
$\frac{7+\sqrt{5}}{7-\sqrt{5}}-\frac{7-\sqrt{5}}{7+\sqrt{5}}=a+\frac{7}{11} \sqrt{5} b$

Simplify the following:
$\frac{3}{\sqrt{8}} + \frac{1}{\sqrt{2}}$

If $\sqrt{2}=1.414$ and $\sqrt{3}=1.732,$ find the value of $\frac{4}{3\sqrt{3}-2\sqrt{2}}+\frac{3}{3\sqrt{3}+2\sqrt{2}}.$

Find the value of $a$ :
$\frac{3-\sqrt{5}}{3+2 \sqrt{5}}=a \sqrt{5}-\frac{19}{11}$

Find the value of the following expression correct to three decimal places, taking $\sqrt{2} = 1.414$, $\sqrt{3} = 1.732$, and $\sqrt{5} = 2.236$:
$\frac{\sqrt{10} - \sqrt{5}}{2}$

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