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(B) Given the expression: $\frac{\sqrt{10} - \sqrt{5}}{2}$We can rewrite $\sqrt{10}$ as $\sqrt{2} 	imes \sqrt{5}$.So, the expression becomes: $\frac{

Vedclass · Accepted Answer

$0.463$

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(B) Given the expression: $\frac{\sqrt{10} - \sqrt{5}}{2}$We can rewrite $\sqrt{10}$ as $\sqrt{2} 	imes \sqrt{5}$.So, the expression becomes: $\frac{\sqrt{2} 	imes \sqrt{5} - \sqrt{5}}{2}$Factor out $\sqrt{5}$ from the numerator: $\frac{\sqrt{5}(\sqrt{2} - 1)}{2}$Substitute the given values $\sqrt{5} = 2.236$ and $\sqrt{2} = 1.414$:$= \frac{2.236(1.414 - 1)}{2}$$= \frac{2.236(0.414)}{2}$$= 1.118 	imes 0.414$$= 0.462852$Rounding to three decimal places, we get $0.463$.

Find the value of the following expression correct to three decimal places, taking $\sqrt{2} = 1.414$, $\sqrt{3} = 1.732$, and $\sqrt{5} = 2.236$:
$\frac{\sqrt{10} - \sqrt{5}}{2}$

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Find the value of the following expression correct to three decimal places, taking $\sqrt{2} = 1.414$, $\sqrt{3} = 1.732$, and $\sqrt{5} = 2.236$:$\frac{\sqrt{10} - \sqrt{5}}{2}$