Rationalise the denominator of the following: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To rationalise the denominator of $\frac{3+\sqrt{2}}{4 \sqrt{2}}$,we multiply both the numerator and the denominator by $\sqrt{2}$:$\frac{3+\sqrt{

Vedclass · Accepted Answer

$\frac{3 \sqrt{2}+2}{8}$

Vedclass · Answer

(B) To rationalise the denominator of $\frac{3+\sqrt{2}}{4 \sqrt{2}}$,we multiply both the numerator and the denominator by $\sqrt{2}$:$\frac{3+\sqrt{2}}{4 \sqrt{2}} = \frac{3+\sqrt{2}}{4 \sqrt{2}} 	imes \frac{\sqrt{2}}{\sqrt{2}}$$= \frac{\sqrt{2}(3+\sqrt{2})}{4 	imes (\sqrt{2} 	imes \sqrt{2})}$$= \frac{3 \sqrt{2} + 2}{4 	imes 2}$$= \frac{3 \sqrt{2} + 2}{8}$

Rationalise the denominator of the following:
$\frac{3+\sqrt{2}}{4 \sqrt{2}}$

Similar Questions

Fill in the blanks to make the following statement true: $\sqrt{49} = \ldots \ldots$

Simplify the following:
$3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$

Rationalise the denominator of the following:
$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

Simplify the following:
$\frac{2 \sqrt{3}}{3} - \frac{\sqrt{3}}{6}$

Simplify: $5 \sqrt{2} + 2 \sqrt{8} - 3 \sqrt{32} + 4 \sqrt{128}$ (in $\sqrt{2}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Rationalise the denominator of the following:$\frac{3+\sqrt{2}}{4 \sqrt{2}}$