Reaction of Br_2 on ethylene in the presence | vedclass

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(C) The reaction of ethylene $(CH_2=CH_2)$ with $Br_2$ in the presence of $NaCl$ involves the formation of a cyclic bromonium ion intermediate. This i

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Both $(a)$ and $(b)$

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(C) The reaction of ethylene $(CH_2=CH_2)$ with $Br_2$ in the presence of $NaCl$ involves the formation of a cyclic bromonium ion intermediate. This intermediate can be attacked by either the bromide ion $(Br^-)$ or the chloride ion $(Cl^-)$ present in the solution. Therefore,the products formed are $1,2$-dibromoethane $(BrCH_2-CH_2Br)$ and $1$-bromo-$2$-chloroethane $(ClCH_2-CH_2Br)$.

Reaction of $Br_2$ on ethylene in the presence of $NaCl$ gives:

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