Represent the following situation in the form of a quadratic equation:
The area of a rectangular plot is $528 \ m^{2}$. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.

(D) Let the breadth of the plot be $x \ m$.
According to the problem,the length of the plot is $(2x + 1) \ m$.
We know that the area of a rectangle is given by the formula: $\text{Area} = \text{Length} \times \text{Breadth}$.
Substituting the given values,we get: $528 = x(2x + 1)$.
Expanding the equation: $528 = 2x^{2} + x$.
Rearranging the terms to form a standard quadratic equation $ax^{2} + bx + c = 0$,we get: $2x^{2} + x - 528 = 0$.