Select the CORRECT order of stability. | vedclass

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Question

(B) The inert pair effect is the tendency of the $ns^2$ electron pair to remain unionized due to the poor shielding of the intervening $d$ and $f$ orb

Vedclass · Accepted Answer

$Sn^{+4} > Sn^{+2}$

Vedclass · Answer

(B) The inert pair effect is the tendency of the $ns^2$ electron pair to remain unionized due to the poor shielding of the intervening $d$ and $f$ orbitals,which increases as we move down a group.In group $14$,the stability of the $+4$ oxidation state decreases down the group,while the stability of the $+2$ oxidation state increases.For $Sn$ ($Group$ $14$),the $+4$ oxidation state is more stable than the $+2$ oxidation state because the inert pair effect is less pronounced in $Sn$ compared to $Pb$.Thus,$Sn^{+4} > Sn^{+2}$ is the correct order of stability.In contrast,$Pb^{+2} > Pb^{+4}$,$Bi^{+3} > Bi^{+5}$,and $PbCl_4 > PbBr_4$ (due to the oxidizing nature of $Pb^{+4}$ and the reducing nature of halides).

Element	Information
$P$	Period number: $2$,Group number: $15$
$Q$	Period number: $3$,Group number: $2$

Select the $CORRECT$ order of stability.

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Consider the following information about elements $P$ and $Q$:

Element Information

$P$ Period number: $2$,Group number: $15$

$Q$ Period number: $3$,Group number: $2$

Then,the formula of the compound formed by elements $P$ and $Q$ is:

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