Simplify: 2 div [2 + 2 div {2 + 2 div (2 + 2 | vedclass

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(C) To simplify the expression,we follow the $BODMAS$ rule (Bracket,Of,Division,Multiplication,Addition,Subtraction).Given expression: $2 \div [2 + 2

Vedclass · Accepted Answer

$\frac{11}{15}$

Vedclass · Answer

(C) To simplify the expression,we follow the $BODMAS$ rule (Bracket,Of,Division,Multiplication,Addition,Subtraction).Given expression: $2 \div [2 + 2 \div \{2 + 2 \div (2 + 2 \div 3)\}]$Step $1$: Solve the innermost bracket $(2 + 2 \div 3) = (2 + \frac{2}{3}) = \frac{6+2}{3} = \frac{8}{3}$.Step $2$: Substitute back into the expression: $2 \div [2 + 2 \div \{2 + 2 \div \frac{8}{3}\}]$.Step $3$: Solve the curly bracket: $2 + 2 \div \frac{8}{3} = 2 + 2 	imes \frac{3}{8} = 2 + \frac{3}{4} = \frac{8+3}{4} = \frac{11}{4}$.Step $4$: Substitute back into the expression: $2 \div [2 + 2 \div \frac{11}{4}]$.Step $5$: Solve the square bracket: $2 + 2 \div \frac{11}{4} = 2 + 2 	imes \frac{4}{11} = 2 + \frac{8}{11} = \frac{22+8}{11} = \frac{30}{11}$.Step $6$: Final division: $2 \div \frac{30}{11} = 2 	imes \frac{11}{30} = \frac{11}{15}$.

Simplify: $2 \div [2 + 2 \div \{2 + 2 \div (2 + 2 \div 3)\}]$

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