The solubility product for salt $AB_2$ is $4 \times 10^{-12}$. Calculate its solubility.

The solubility of $PbF_2$ (formula weight $= 245$) is $0.46 \ g/L$. What is the solubility product?

In $1 \ L$ saturated solution of $AgCl$ $[K_{sp}(AgCl)=1.6 \times 10^{-10}]$,$0.1 \ mol$ of $CuCl$ $[K_{sp}(CuCl)=1.0 \times 10^{-6}]$ is added. The resultant concentration of $Ag^{+}$ in the solution is $1.6 \times 10^{-x}$. The value of $x$ is

If $H_2S$ is passed in a solution of $0.1 \ M \ Zn^{2+}$ and $0.01 \ M \ Cu^{+}$ and the concentration of $S^{2-}$ is made $8.1 \times 10^{-31} \ M$. Which precipitation of $ZnS$ and $CuS$ will take place? Given: $K_{sp}(ZnS) = 3.0 \times 10^{-23}$ and $K_{sp}(CuS) = 8.0 \times 10^{-34}$.

At $20\,^oC$,the concentration of $Ag^{+}$ in a saturated solution of $Ag_2CrO_4$ is $1.5 \times 10^{-4}\,mol\,L^{-1}$. The solubility product of $Ag_2CrO_4$ at $20\,^oC$ is .......

Explain the difference between ionic product and solubility product. Explain the condition for the precipitation of a sparingly soluble salt.