The solubility of $PbF_2$ (formula weight $= 245$) is $0.46 \ g/L$. What is the solubility product?

  • A
    $1.1 \times 10^{-10}$
  • B
    $2.6 \times 10^{-8}$
  • C
    $1.1 \times 10^{-7}$
  • D
    $6.8 \times 10^{-9}$

Explore More

Similar Questions

The solubility product of $As_2S_3$ is $2.8 \times 10^{-72}$. What is the solubility of $As_2S_3$?

Calculate the solubility in $mol \ dm^{-3}$ of sparingly soluble salt $BA$ if its solubility product is $4.9 \times 10^{-13}$ at the same temperature.

The solubility products of $NiS$,$ZnS$,$CdS$,and $HgS$ are $4.7 \times 10^{-5}$,$1.6 \times 10^{-24}$,$8 \times 10^{-27}$,and $4 \times 10^{-53}$ respectively. An aqueous solution contains $Ni^{2+}$,$Zn^{2+}$,$Cd^{2+}$,and $Hg^{2+}$ of equal concentration. $H_2S$ gas was passed into this solution very slowly. The first and the last ions that precipitate as sulphides are respectively.

The solubility product of $AB_2$ is $8 \times 10^{-5} \ M^3$. If the salt is $80 \ \%$ dissociated in a saturated solution,find the solubility of the salt in $M$.

In an aqueous solution containing $AgCl_{(s)}$,$AgBr_{(s)}$,and $AgI_{(s)}$,find the ratio $[Cl^{-}] : [Br^{-}] : [I^{-}]$ at equilibrium if $K_{sp}(AgCl) = 10^{-10}$,$K_{sp}(AgBr) = 10^{-13}$,and $K_{sp}(AgI) = 10^{-16}$.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo