Solve the following inequality: $|4-x|+1 < 3$
- A$x \in (2, 6)$
- B$x \in (0, 4)$
- C$x \in (-2, 2)$
- D$x \in (4, 8)$
Explore More
Similar Questions
Solve $5x - 3 < 7$,when $x$ is a real number.
Easy
View SolutionSolve the following inequality and represent it on a number line: $\frac{x-1}{2}+5 \geq \frac{2x-1}{3}+15$
Easy
View SolutionLet $a, b, c, d, e$ be real numbers such that $a + b < c + d$,$b + c < d + e$,$c + d < e + a$,and $d + e < a + b$. Then,
DifficultKVPY 2017
View SolutionThe set $\{x \in R: 16(2^x) > 16^{-1/x}\} = $
Solve the given inequality for real $x$: $\frac{1}{2}\left(\frac{3x}{5}+4\right) \geq \frac{1}{3}(x-6)$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo