Solve the given inequality for real x: frac{x | vedclass

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Question

(A) Given inequality: $\frac{x}{3} > \frac{x}{2} + 1$Subtract $\frac{x}{2}$ from both sides:$\frac{x}{3} - \frac{x}{2} > 1$Find a common denominator $

Vedclass · Accepted Answer

$(-\infty, -6)$

Vedclass · Answer

(A) Given inequality: $\frac{x}{3} > \frac{x}{2} + 1$Subtract $\frac{x}{2}$ from both sides:$\frac{x}{3} - \frac{x}{2} > 1$Find a common denominator $(6)$:$\frac{2x - 3x}{6} > 1$Simplify the numerator:$-\frac{x}{6} > 1$Multiply both sides by $6$:$-x > 6$Multiply by $-1$ and reverse the inequality sign:$x Thus,the solution set is $(-\infty, -6)$.

Solve the given inequality for real $x$: $\frac{x}{3} > \frac{x}{2} + 1$

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