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(B) For equation $I$: $12x^2 - 47x + 40 = 0$Splitting the middle term: $12x^2 - 32x - 15x + 40 = 0$$4x(3x - 8) - 5(3x - 8) = 0$$(4x - 5)(3x - 8) = 0$S

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if $x \ge y$

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(B) For equation $I$: $12x^2 - 47x + 40 = 0$Splitting the middle term: $12x^2 - 32x - 15x + 40 = 0$$4x(3x - 8) - 5(3x - 8) = 0$$(4x - 5)(3x - 8) = 0$So,$x = \frac{5}{4} = 1.25$ and $x = \frac{8}{3} \approx 2.67$.For equation $II$: $4y^2 + 3y - 10 = 0$Splitting the middle term: $4y^2 + 8y - 5y - 10 = 0$$4y(y + 2) - 5(y + 2) = 0$$(4y - 5)(y + 2) = 0$So,$y = \frac{5}{4} = 1.25$ and $y = -2$.Comparing the values:$x_1 = 1.25, x_2 = 2.67$$y_1 = 1.25, y_2 = -2$Since $x_1 = y_1$,$x_2 > y_1$,and $x_1, x_2 > y_2$,we conclude that $x \ge y$.

Solve the given two equations and select the correct option.
$I.$ $12x^2 - 47x + 40 = 0$
$II.$ $4y^2 + 3y - 10 = 0$

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Solve the given two equations and select the correct option.$I.$ $12x^2 - 47x + 40 = 0$$II.$ $4y^2 + 3y - 10 = 0$