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(C) Step $1$: Solve for $x$.$x = \frac{\sqrt{256}}{\sqrt{576}} = \frac{16}{24} = \frac{2}{3} \approx 0.666$.Step $2$: Solve the quadratic equation $3y

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if $x \ge y$

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(C) Step $1$: Solve for $x$.$x = \frac{\sqrt{256}}{\sqrt{576}} = \frac{16}{24} = \frac{2}{3} \approx 0.666$.Step $2$: Solve the quadratic equation $3y^2 + y - 2 = 0$.Using the factorization method: $3y^2 + 3y - 2y - 2 = 0$.$3y(y + 1) - 2(y + 1) = 0$.$(3y - 2)(y + 1) = 0$.So,$y = \frac{2}{3}$ or $y = -1$.Step $3$: Compare $x$ and $y$.$x = \frac{2}{3}$.The values of $y$ are $\frac{2}{3}$ and $-1$.Since $x = \frac{2}{3}$ and $y$ can be $\frac{2}{3}$ or $-1$,we observe that $x \ge y$ (because $x$ is equal to one value of $y$ and greater than the other value of $y$).

Solve the given two equations and select the correct option.
$I.$ $x = \frac{\sqrt{256}}{\sqrt{576}}$
$II.$ $3y^2 + y - 2 = 0$

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Solve the given two equations and select the correct option.$I.$ $x = \frac{\sqrt{256}}{\sqrt{576}}$$II.$ $3y^2 + y - 2 = 0$