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(D) From equation $I$: $x^{2} = 3481 \Rightarrow x = \pm 59$.From equation $II$: $3y^{2} = \sqrt[3]{216000}$.Since $60^{3} = 216000$,we have $3y^{2} =

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if $x = y$ or the relationship between $x$ and $y$ cannot be established.

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(D) From equation $I$: $x^{2} = 3481 \Rightarrow x = \pm 59$.From equation $II$: $3y^{2} = \sqrt[3]{216000}$.Since $60^{3} = 216000$,we have $3y^{2} = 60 \Rightarrow y^{2} = 20 \Rightarrow y = \pm \sqrt{20} \approx \pm 4.47$.Comparing the values:If $x = 59$,then $x > y$ (since $59 > 4.47$ and $59 > -4.47$).If $x = -59$,then $x Since we get different results for different values of $x$,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2} - 3481 = 0$
$II.$ $3y^{2} = \sqrt[3]{216000}$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{2} - 3481 = 0$$II.$ $3y^{2} = \sqrt[3]{216000}$