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(A) $I.$ $99 x^{2} + 149 x + 56 = 0$$99 x^{2} + 77 x + 72 x + 56 = 0$$11 x(9 x + 7) + 8(9 x + 7) = 0$$(9 x + 7)(11 x + 8) = 0$$x = -\frac{7}{9} \appro

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if $x > y$

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(A) $I.$ $99 x^{2} + 149 x + 56 = 0$$99 x^{2} + 77 x + 72 x + 56 = 0$$11 x(9 x + 7) + 8(9 x + 7) = 0$$(9 x + 7)(11 x + 8) = 0$$x = -\frac{7}{9} \approx -0.777$$x = -\frac{8}{11} \approx -0.727$$II.$ $156 y^{2} + 287 y + 132 = 0$$156 y^{2} + 143 y + 144 y + 132 = 0$$13 y(12 y + 11) + 12(12 y + 11) = 0$$(12 y + 11)(13 y + 12) = 0$$y = -\frac{11}{12} \approx -0.916$$y = -\frac{12}{13} \approx -0.923$Comparing the values:$x$ values are approximately $-0.777$ and $-0.727$.$y$ values are approximately $-0.916$ and $-0.923$.Since all values of $x$ are greater than all values of $y$,we have $x > y$.

Solve the given two equations and choose the correct option.
$I.$ $99 x^{2} + 149 x + 56 = 0$
$II.$ $156 y^{2} + 287 y + 132 = 0$

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Solve the given two equations and choose the correct option.$I.$ $99 x^{2} + 149 x + 56 = 0$$II.$ $156 y^{2} + 287 y + 132 = 0$