Solve the given two equations and select the correct answer from the given options.
$I.$ $(441)^{\frac{1}{2}} x^{2} - 111 = (15)^{2}$
$II.$ $\sqrt{121} y^{2} + (6)^{3} = 260$

  • A
    if $x > y$
  • B
    if $x < y$
  • C
    if $x \ge y$
  • D
    if $x = y$ or relationship between $x$ and $y$ cannot be established.

Explore More

Similar Questions

The roots of the given equation $2(a^2 + b^2)x^2 + 2(a + b)x + 1 = 0$ are

If $a=b=c,$ then find the value of $\frac{(a+b+c)^{2}}{a^{2}+b^{2}+c^{2}}.$

Solve the given two equations and select the correct option.
$I.$ $x = \sqrt[3]{2744}$
$II.$ $y = \sqrt{487}$

Both the roots of the given equation $(x - a)(x - b) + (x - b)(x - c) + (x - c)(x - a) = 0$ are always

If $3$ is a root of the equation ${x^2} + kx - 24 = 0,$ then $3$ is also a root of which of the following equations?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo