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(A) For equation $I$: $16 x^{2}+20 x+6=0$Dividing by $2$,we get $8 x^{2}+10 x+3=0$.Factoring the quadratic: $8 x^{2}+4 x+6 x+3=0 \Rightarrow 4 x(2 x+1

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$x > y$

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(A) For equation $I$: $16 x^{2}+20 x+6=0$Dividing by $2$,we get $8 x^{2}+10 x+3=0$.Factoring the quadratic: $8 x^{2}+4 x+6 x+3=0 \Rightarrow 4 x(2 x+1)+3(2 x+1)=0$.So,$(4 x+3)(2 x+1)=0$.The roots are $x = -0.75$ and $x = -0.5$.For equation $II$: $10 y^{2}+38 y+24=0$Dividing by $2$,we get $5 y^{2}+19 y+12=0$.Factoring the quadratic: $5 y^{2}+15 y+4 y+12=0 \Rightarrow 5 y(y+3)+4(y+3)=0$.So,$(5 y+4)(y+3)=0$.The roots are $y = -0.8$ and $y = -3$.Comparing the values:$x$ values are $\{-0.75, -0.5\}$ and $y$ values are $\{-3, -0.8\}$.Since $-0.75 > -0.8$,$-0.75 > -3$,$-0.5 > -0.8$,and $-0.5 > -3$,it follows that $x > y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $16 x^{2}+20 x+6=0$
$II.$ $10 y^{2}+38 y+24=0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $16 x^{2}+20 x+6=0$$II.$ $10 y^{2}+38 y+24=0$