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(D) Step $1$: Solve equation $I$ for $x$.$x^{4} - 227 = 398$$x^{4} = 398 + 227 = 625$$x = \pm \sqrt[4]{625} = \pm 5$So,$x = 5$ or $x = -5$.Step $2$: S

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if $x = y$ or the relationship cannot be established.

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(D) Step $1$: Solve equation $I$ for $x$.$x^{4} - 227 = 398$$x^{4} = 398 + 227 = 625$$x = \pm \sqrt[4]{625} = \pm 5$So,$x = 5$ or $x = -5$.Step $2$: Solve equation $II$ for $y$.$y^{2} + 321 = 346$$y^{2} = 346 - 321 = 25$$y = \pm \sqrt{25} = \pm 5$So,$y = 5$ or $y = -5$.Step $3$: Compare the values of $x$ and $y$.If $x = 5$,$y$ can be $5$ $(x = y)$ or $-5$ $(x > y)$.If $x = -5$,$y$ can be $5$ $(x Since the relationship varies depending on the chosen values,the relationship cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{4} - 227 = 398$
$II.$ $y^{2} + 321 = 346$

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$I. \quad p^{2}-18 p+77=0$
$II. \quad 3 q^{2}-25 q+28=0$
$Quantity \, 1$: Value of $p$
$Quantity \, 2$: Value of $q$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{4} - 227 = 398$$II.$ $y^{2} + 321 = 346$