The square root of frac{(0.75)^{3}}{1-0.75} + | vedclass

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(B) Let the expression be $E = \frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$.First,simplify the fraction: $\frac{(0.75)^{3}}{0.25} = \frac{(0.75)

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$2$

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(B) Let the expression be $E = \frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$.First,simplify the fraction: $\frac{(0.75)^{3}}{0.25} = \frac{(0.75)^{3}}{(0.75/3)} = 3 	imes (0.75)^{2}$.Now,substitute this back into the expression: $E = 3 	imes (0.75)^{2} + 0.75^{2} + 0.75 + 1$.Combine the terms: $E = 4 	imes (0.75)^{2} + 0.75 + 1$.Calculate the values: $4 	imes (0.5625) + 0.75 + 1 = 2.25 + 0.75 + 1 = 4$.The square root of the expression is $\sqrt{4} = 2$.

The square root of $\frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$ is

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