State the electronic configurations of group-$16$ elements.
The elements of group-$16$ have six electrons in their valence shell. Hence,the general valence shell electronic configuration is $ns^{2} np^{4}$.
| Element | Electronic configuration |
| $_{8}O$ | $[He] 2s^{2} 2p^{4}$ |
| $_{16}S$ | $[Ne] 3s^{2} 3p^{4}$ |
| $_{34}Se$ | $[Ar] 3d^{10} 4s^{2} 4p^{4}$ |
| $_{52}Te$ | $[Kr] 4d^{10} 5s^{2} 5p^{4}$ |
| $_{84}Po$ | $[Xe] 4f^{14} 5d^{10} 6s^{2} 6p^{4}$ |
| $_{116}Lv$ | $[Rn] 5f^{14} 6d^{10} 7s^{2} 7p^{4}$ |
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Similar Questions
Match List-$I$ with List-$II$ :
List-$I$ (Oxoacids of Sulphur) List-$II$ (Bonds) $A$. Peroxodisulphuric acid $I$. Two $S-OH$,Four $S=O$,One $S-O-S$ $B$. Sulphuric acid $II$. Two $S-OH$,One $S=O$ $C$. Pyrosulphuric acid $III$. Two $S-OH$,Four $S=O$,One $S-O-O-S$ $D$. Sulphurous acid $IV$. Two $S-OH$,Two $S=O$
Choose the correct answer from the options given below.
| List-$I$ (Oxoacids of Sulphur) | List-$II$ (Bonds) |
| $A$. Peroxodisulphuric acid | $I$. Two $S-OH$,Four $S=O$,One $S-O-S$ |
| $B$. Sulphuric acid | $II$. Two $S-OH$,One $S=O$ |
| $C$. Pyrosulphuric acid | $III$. Two $S-OH$,Four $S=O$,One $S-O-O-S$ |
| $D$. Sulphurous acid | $IV$. Two $S-OH$,Two $S=O$ |
Choose the correct answer from the options given below.
MediumNEET 2023
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