Structure of IF_6^- is : | vedclass

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Question

(B) To determine the structure of $IF_6^-$,we calculate the number of electron pairs around the central iodine atom $(I)$.The central atom $I$ has $7$

Vedclass · Accepted Answer

Distorted octahedral

Vedclass · Answer

(B) To determine the structure of $IF_6^-$,we calculate the number of electron pairs around the central iodine atom $(I)$.The central atom $I$ has $7$ valence electrons.Adding $1$ electron from the negative charge gives $8$ electrons.It forms $6$ bonds with fluorine atoms,using $6$ electrons.This leaves $2$ electrons,which form $1$ lone pair.Total electron pairs = $6$ (bond pairs) + $1$ (lone pair) = $7$ electron pairs.According to $VSEPR$ theory,$7$ electron pairs correspond to a pentagonal bipyramidal electron geometry.With $6$ bond pairs and $1$ lone pair,the molecular geometry is distorted octahedral.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

Structure of $IF_6^-$ is :

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$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal

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