Match List-I with List-II: List-I (Molec | vedclass

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(D) The molecular shapes are determined by $VSEPR$ theory:$1$. $BrF_5$: Central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in a square p

Vedclass · Accepted Answer

$A-IV, B-III, C-I, D-II$

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(D) The molecular shapes are determined by $VSEPR$ theory:$1$. $BrF_5$: Central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in a square pyramidal shape $(A-IV)$.$2$. $H_2O$: Central atom $O$ has $2$ bond pairs and $2$ lone pairs,resulting in a bent shape $(B-III)$.$3$. $ClF_3$: Central atom $Cl$ has $3$ bond pairs and $2$ lone pairs,resulting in a $T$-shape $(C-I)$.$4$. $SF_4$: Central atom $S$ has $4$ bond pairs and $1$ lone pair,resulting in a see-saw shape $(D-II)$.Therefore,the correct matching is $A-IV, B-III, C-I, D-II$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $BrF_5$ $I$. $T$-shape

$B$. $H_2O$ $II$. See-saw

$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal

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Match List-$I$ with List-$II$: List-$I$ (Molecule) List-$II$ (Shape) $A$. $BrF_5$ $I$. $T$-shape $B$. $H_2O$ $II$. See-saw $C$. $ClF_3$ $III$. Bent $D$. $SF_4$ $IV$. Square pyramidal