SubstanceGlomerular filtrateReabsorbedUrine(i | vedclass

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(C) $1$. Statement $(a)$: The table shows $162 \,g$ of glucose in the glomerular filtrate and $162 \,g$ reabsorbed,resulting in $0 \,g$ in the urine.

Vedclass · Accepted Answer

$a, b$ and $d$

Vedclass · Answer

(C) $1$. Statement $(a)$: The table shows $162 \,g$ of glucose in the glomerular filtrate and $162 \,g$ reabsorbed,resulting in $0 \,g$ in the urine. This confirms glucose is completely reabsorbed. Statement $(a)$ is correct.$2$. Statement $(b)$: The table shows $54 \,g$ of urea in the filtrate and $24 \,g$ reabsorbed,leaving $30 \,g$ in the urine. This indicates partial reabsorption. Statement $(b)$ is correct.$3$. Statement $(c)$: Proteins are generally not filtered in significant amounts by the glomerulus. The presence of $0.1 \,g$ in urine is negligible and does not indicate active secretion. Statement $(c)$ is incorrect.$4$. Statement $(d)$: The table shows $1.6 \,g$ of creatinine in the filtrate and $1.7 \,g$ in the urine,with $0 \,g$ reabsorbed. The increase from $1.6 \,g$ to $1.7 \,g$ indicates that creatinine is actively secreted into the renal tubules. Statement $(d)$ is correct.$5$. Therefore,statements $(a), (b),$ and $(d)$ are correct.

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Substance	Glomerular filtrate	Reabsorbed	Urine
$(i)$ Proteins	$2 \,g$	$1.9 \,g$	$0.1 \,g$
$(ii)$ Glucose	$162 \,g$	$162 \,g$	$0 \,g$
$(iii)$ Urea	$54 \,g$	$24 \,g$	$30 \,g$
$(iv)$ Creatinine	$1.6 \,g$	$0 \,g$	$1.7 \,g$