Taking the Earth to be a metallic sphere,its capacity will approximately be

Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is (in $\times$)

For the shown situation,in the steady state condition,the ratio of the charge stored in the first capacitor to the charge stored in the $n^{th}$ capacitor is:

The radii of the inner and outer spheres of a spherical capacitor are $8 \ cm$ and $9 \ cm$ respectively. The outer sphere is earthed and the inner sphere is charged. If the space between the concentric spheres is filled with a liquid of dielectric constant $5$,the capacitance of the capacitor is:

The unit of electric permittivity is

If $27$ identical charged conducting spheres each of capacitance $10 \mu F$ combine to form a big sphere,then the capacitance of the big sphere is: (in $\mu F$)