The $K_c$ for $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$ is $64$. If the volume of the container is reduced to one-half of its original volume,the value of the equilibrium constant will be

  • A
    $28$
  • B
    $64$
  • C
    $32$
  • D
    $16$

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