The X-X bond length is 1.00 mathring{A} and C | vedclass

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(C) The covalent radii are calculated as $r_X = \frac{1.00}{2} = 0.50 \mathring{A}$ and $r_C = \frac{1.54}{2} = 0.77 \mathring{A}$.Using the Schomaker

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$1.18$

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(C) The covalent radii are calculated as $r_X = \frac{1.00}{2} = 0.50 \mathring{A}$ and $r_C = \frac{1.54}{2} = 0.77 \mathring{A}$.Using the Schomaker-Stevenson equation for bond length: $d_{C-X} = r_C + r_X - 0.09 |\chi_C - \chi_X|$.Substituting the values: $d_{C-X} = 0.77 + 0.50 - 0.09 |2.0 - 3.0|$.$d_{C-X} = 1.27 - 0.09(1) = 1.18 \mathring{A}$.

The $X-X$ bond length is $1.00 \mathring{A}$ and $C-C$ bond length is $1.54 \mathring{A}$. If $EN$ of $X$ and $C$ are $3.0$ and $2.0$ respectively,the $C-X$ bond length is likely to be ............ $\mathring{A}$.

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