The LCM of two prime numbers x and y (x y | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given that the $LCM$ of two prime numbers $x$ and $y$ is $161$.Since $x$ and $y$ are prime numbers,their $HCF$ is $1$.We know that for any two num

Vedclass · Accepted Answer

$-2$

Vedclass · Answer

(A) Given that the $LCM$ of two prime numbers $x$ and $y$ is $161$.Since $x$ and $y$ are prime numbers,their $HCF$ is $1$.We know that for any two numbers,$LCM 	imes HCF = 	ext{Product of the numbers}$.Therefore,$x 	imes y = 161$.By prime factorization of $161$,we get $161 = 7 	imes 23$.Since $x > y$,we assign $x = 23$ and $y = 7$.Now,calculating the value of $3y - x$:$3(7) - 23 = 21 - 23 = -2$.

The $LCM$ of two prime numbers $x$ and $y$ $(x > y)$ is $161$. The value of $3y - x$ is

Similar Questions

The $HCF$ of two numbers is $8$. Which one of the following can never be their $LCM$?

Find the greatest number of five digits which when divided by $12, 15, 21, 25$ and $28$ leaves $5, 8, 14, 18$ and $21$ as remainders, respectively.

Find the greatest number of $4$ digits and the least number of $5$ digits that have $196$ as their $HCF$.

Let $N$ be the greatest number that will divide $1305, 4665,$ and $6905,$ leaving the same remainder in each case. Then the sum of the digits in $N$ is:

The greatest number that divides $43, 91,$ and $183$ so as to leave the same remainder in each case is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module