The H.C.F. of two numbers is 12 and their dif | vedclass

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(D) Let the two numbers be $12x$ and $12y$,where $x$ and $y$ are coprime integers and $x < y$.Since the $H.C.F.$ is $12$,both numbers must be multiple

Vedclass · Accepted Answer

$84, 96$

Vedclass · Answer

(D) Let the two numbers be $12x$ and $12y$,where $x$ and $y$ are coprime integers and $x Since the $H.C.F.$ is $12$,both numbers must be multiples of $12$.The difference between the numbers is given as $12y - 12x = 12$,which simplifies to $y - x = 1$.This means the numbers are consecutive multiples of $12$.Checking the options:For $84$ and $96$: $H.C.F.(84, 96) = 12$ and $96 - 84 = 12$.Thus,the numbers are $84$ and $96$.

The $H.C.F.$ of two numbers is $12$ and their difference is $12$. The numbers are:

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