The n^{th} term of an A.P. is given by T_{n} | vedclass

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(D) Given the $n^{th}$ term of the $A.P.$ is $T_{n} = 7 - 3n$.To find the first term $(a)$,substitute $n = 1$:$a = T_{1} = 7 - 3(1) = 4$.To find the $

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$-800$

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(D) Given the $n^{th}$ term of the $A.P.$ is $T_{n} = 7 - 3n$.To find the first term $(a)$,substitute $n = 1$:$a = T_{1} = 7 - 3(1) = 4$.To find the $25^{th}$ term $(T_{25})$,substitute $n = 25$:$T_{25} = 7 - 3(25) = 7 - 75 = -68$.The sum of the first $n$ terms of an $A.P.$ is given by $S_{n} = \frac{n}{2}(a + T_{n})$.For $n = 25$:$S_{25} = \frac{25}{2}(4 + (-68))$$S_{25} = \frac{25}{2}(-64)$$S_{25} = 25 	imes (-32) = -800$.Thus,the sum of the first $25$ terms is $-800$.

The $n^{th}$ term of an $A.P.$ is given by $T_{n} = 7 - 3n$. Find the sum of the first $25$ terms of the $A.P.$

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