The n^{th} term of an A.P. is given by T_{n} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The $n^{th}$ term of the $A.P.$ is given by $T_{n} = 3n - 1$.To find the common difference $d$,we calculate the first two terms of the sequence.Fo

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The $n^{th}$ term of the $A.P.$ is given by $T_{n} = 3n - 1$.To find the common difference $d$,we calculate the first two terms of the sequence.For $n = 1$,$T_{1} = 3(1) - 1 = 3 - 1 = 2$.For $n = 2$,$T_{2} = 3(2) - 1 = 6 - 1 = 5$.The common difference $d$ is defined as $d = T_{2} - T_{1}$.Substituting the values,$d = 5 - 2 = 3$.Thus,the common difference of the $A.P.$ is $3$.

The $n^{th}$ term of an $A.P.$ is given by $T_{n} = 3n - 1$. Then,the common difference of the $A.P.$ is ...........

Similar Questions

Find the number of terms in the finite $A.P.$ $7, 11, 15, \ldots, 107$.

For the $AP: -3, -7, -11, \ldots,$ can we find $a_{30} - a_{20}$ directly without actually finding $a_{30}$ and $a_{20}$? Give reasons for your answer.

For an $A.P.$,five times the $5^{th}$ term is equal to eight times the $8^{th}$ term. Find the $13^{th}$ term of the $A.P.$

Which term of the $A.P.$ $20, 19 \frac{1}{4}, 18 \frac{1}{2}, 17 \frac{3}{4}, \ldots$ is its first negative term (in $^{th}$)?

The $4^{\text{th}}$ term from the end of the $AP: -11, -8, -5, \dots, 49$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module