The pH of 10^{-8} M HCl solution is | vedclass

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(B) Since $HCl$ is an acid,its $pH$ must be less than $7$. For very dilute solutions of strong acids,the contribution of $H^+$ ions from the auto-ioni

Vedclass · Accepted Answer

$6.9586$

Vedclass · Answer

(B) Since $HCl$ is an acid,its $pH$ must be less than $7$. For very dilute solutions of strong acids,the contribution of $H^+$ ions from the auto-ionization of water cannot be neglected. From $HCl$,$[H^+]_{acid} = 10^{-8} \ M$. From water,$[H^+]_{water} = 10^{-7} \ M$. Total $[H^+] = 10^{-8} + 10^{-7} = 10^{-8}(1 + 10) = 11 	imes 10^{-8} \ M$. $pH = -\log[H^+] = -\log(11 	imes 10^{-8}) = -(\log 11 + \log 10^{-8}) = -(1.0414 - 8) = 6.9586$.

The $pH$ of $10^{-8} \ M \ HCl$ solution is

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