The Delta_0 of a coordination complex of a me | vedclass

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(B) Given,$\Delta_0$ for the coordination complex is $1000 \ kJ \ mol^{-1}$.Energy of $t_{2g}$ orbitals,$E(t_{2g}) = -400 \ kJ \ mol^{-1}$.We know tha

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$ 600 $

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(B) Given,$\Delta_0$ for the coordination complex is $1000 \ kJ \ mol^{-1}$.Energy of $t_{2g}$ orbitals,$E(t_{2g}) = -400 \ kJ \ mol^{-1}$.We know that the crystal field splitting energy $\Delta_0$ is defined as the difference between the energies of $e_g$ and $t_{2g}$ orbitals:$\Delta_0 = E(e_g) - E(t_{2g})$Substituting the given values:$1000 = E(e_g) - (-400)$$1000 = E(e_g) + 400$$E(e_g) = 1000 - 400$$E(e_g) = 600 \ kJ \ mol^{-1}$Thus,the energy of $e_g$ orbitals is $600 \ kJ \ mol^{-1}$.Therefore,option $(B)$ is the correct answer.

List-$I$ (Coordination entity)	List-$II$ (Wavelength of light absorbed in $nm$)
$A$. $[CoCl(NH_3)_5]^{2+}$	$I$. $310$
$B$. $[Co(NH_3)_6]^{3+}$	$II$. $475$
$C$. $[Co(CN)_6]^{3-}$	$III$. $535$
$D$. $[Cu(H_2O)_4]^{2+}$	$IV$. $600$

The $\Delta_0$ of a coordination complex of a metal ion $(3d^1)$ is $1000 \ kJ \ mol^{-1}$. If the energy of $t_{2g}$ orbitals is $-400 \ kJ \ mol^{-1}$,the energy (in $kJ \ mol^{-1}$) of $e_g$ orbitals is

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