The absolute configuration of the given molec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the absolute configuration,we assign priorities to the groups attached to each chiral center using the Cahn-Ingold-Prelog $(CIP)$ rul

Vedclass · Accepted Answer

$R, R$

Vedclass · Answer

(B) To determine the absolute configuration,we assign priorities to the groups attached to each chiral center using the Cahn-Ingold-Prelog $(CIP)$ rules.For the first chiral center (left): The groups are $-OH$ $(1)$,$-COOH$ $(2)$,$-CH(OH)COOH$ $(3)$,and $-H$ $(4)$. Since $-H$ is on a dashed bond (pointing away),the sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,which corresponds to the $R$ configuration.For the second chiral center (right): The groups are $-OH$ $(1)$,$-COOH$ $(2)$,$-CH(OH)COOH$ $(3)$,and $-H$ $(4)$. Since $-H$ is on a dashed bond (pointing away),the sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,which corresponds to the $R$ configuration.Thus,the absolute configuration is $R, R$.

The absolute configuration of the given molecule is:

Similar Questions

Which of the following is optically inactive?

The number of optical isomers for the compound $CH_3-CH(OH)-CH(Cl)-CH_2-COOH$ is:

Which of the following compounds will exhibit optical isomerism?

Meso-tartaric acid is optically inactive due to the presence of

Which of the following compounds is not chiral?

Vedclass Test Series

Exam Paper Generator

Online Exam Module