The acceleration of a particle which moves along the positive $x$-axis varies with its position as shown in the graph. If the velocity of the particle is $0.8 \ m/s$ at $x = 0$,find the velocity of the particle at $x = 1.4 \ m$ (in $m/s$).

  • A
    $1.6$
  • B
    $1.2$
  • C
    $1.4$
  • D
    none of these

Explore More

Similar Questions

When does a particle experience retardation (deceleration)?

$A$ body is moving according to the equation $x = at + bt^2 - ct^3$,where $x$ is displacement and $a, b,$ and $c$ are constants. The acceleration of the body is:

If the velocity of a particle is $(10 + 2t^2) \ m/s$,then the average acceleration of the particle between $2 \ s$ and $5 \ s$ is..........$m/s^2$.

The position $x$ of a particle varies with time $t$ as $x = at^2 - bt^3$. The acceleration of the particle will be zero at time $t$ equal to

The acceleration-time graph is given. If the initial velocity is $5\,m/s$,then the velocity after $2\,s$ is.......$m/s$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo