The activation energy of a reaction can be determined from the slope of which of the following graphs?

  • A
    $\ln k$ vs. $\frac{1}{T}$
  • B
    $\frac{T}{\ln k}$ vs. $\frac{1}{T}$
  • C
    $\ln k$ vs. $T$
  • D
    $\frac{\ln k}{T}$ vs. $T$

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The rate of a certain biochemical reaction at physiological temperature $T$ occurs $10^{6}$ times faster with an enzyme than without. The change in the activation energy upon adding the enzyme is

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The temperature dependence of the rate constant $k$ is expressed as $k = A e^{-E_a / RT}$. When a plot between $\log k$ and $1/T$ is plotted,we get the graph as shown. What is the value of the slope in the graph?

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