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(C) According to Lenz's Law, the induced current will flow in a direction such that it opposes the change in magnetic flux. In case $I$, the magnetic

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from $b$ to $a$ and from $d$ to $c$

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(C) According to Lenz's Law, the induced current will flow in a direction such that it opposes the change in magnetic flux. In case $I$, the magnetic field $B$ is directed into the plane $(\otimes)$ and is decreasing. To oppose this decrease, the induced magnetic field must also be directed into the plane $(\otimes)$. Using the right-hand thumb rule, for the induced magnetic field to be into the plane, the induced current must flow in a clockwise direction. For the larger square loop $(ahgb)$, the clockwise direction corresponds to the path $a \rightarrow h \rightarrow g \rightarrow b \rightarrow a$, so the current flows from $b$ to $a$ in the segment $ab$. For the smaller square loop $(cdef)$, the clockwise direction corresponds to the path $c \rightarrow d \rightarrow e \rightarrow f \rightarrow c$, so the current flows from $d$ to $c$ in the segment $cd$. Therefore, the current flows from $b$ to $a$ and from $d$ to $c$. Thus, option $C$ is correct.

The adjoining figure shows two different arrangements in which two square wire frames are placed in a uniform constantly decreasing magnetic field $B$. The direction of induced current in the case $I$ is

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