The amount of heat energy required to raise t | vedclass

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Question

(D) Helium is a monoatomic gas,so its degree of freedom $f = 3$.For a gas at constant volume,the heat energy required is given by $\Delta Q = \mu C_V

Vedclass · Accepted Answer

$\frac{3}{8}N_Ak_B(T_2-T_1)$

Vedclass · Answer

(D) Helium is a monoatomic gas,so its degree of freedom $f = 3$.For a gas at constant volume,the heat energy required is given by $\Delta Q = \mu C_V \Delta T$.The number of moles $\mu = \frac{	ext{mass}}{	ext{molar mass}} = \frac{1\, g}{4\, g/mol} = \frac{1}{4}\, mol$.The molar heat capacity at constant volume is $C_V = \frac{fR}{2} = \frac{3R}{2}$.Substituting these values,we get $\Delta Q = \frac{1}{4} 	imes \frac{3R}{2} 	imes (T_2 - T_1) = \frac{3R}{8}(T_2 - T_1)$.Since the universal gas constant $R = N_A k_B$,the heat energy is $\Delta Q = \frac{3}{8} N_A k_B (T_2 - T_1)$.

$X=x$	$P(X=x)$
$0$	$0.4$
$1$	$0.3$
$2$	$0.1$
$3$	$0.1$
$4$	$0.1$

The amount of heat energy required to raise the temperature of $1\, g$ of Helium at $NTP$ from $T_1\, K$ to $T_2\, K$ is

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