The angle $A$ of $\triangle ABC$ is found by measurement to be $67 \frac{1}{2}^{\circ}$ and the area of $\triangle ABC$ is calculated from the measurements of $b, c, A$. In measuring $A$,an error of $9 \text{ min}$ is made. Then the percentage error in the area of the triangle is

  • A
    $\frac{\pi}{6}(2-\sqrt{3})$
  • B
    $\frac{\pi}{6}(2+\sqrt{3})$
  • C
    $\frac{\pi}{12}(\sqrt{2}+1)$
  • D
    $\frac{\pi}{12}(\sqrt{2}-1)$

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